IF the measurement is equal then the odd man is 12. Weigh the lighter of the 2 men against any other neutral man. We know {9,10,11,12} all weigh the same. There was a problem preparing your codespace, please try again. WRONG! (seesaw measurement number 3), (first make sure you have the heavy side on the left), seesaw: L1 L2 L3 L4 (heavy) R1 R2 R3 R4 You will have to be logical in your reasoning. Work fast with our official CLI. Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. I later went back and refined it a little, so here it is. Use the weight difference from step 1 to determine heavier lighter. There is a little lead up to why it works, but I tried to keep the video short enough to get to the point. The island has no scales but there is a see-saw. Proceed to step 2. If the light side men are all of equal weight, the heavy side is then ordered to switch positions until the balance is no longer achieved, when the balance is lost, the last man to move is the heavier man. if balanced it is L4 - else it is the heavier of L2 and L3. (seesaw measurement number 3), 2.A.2 if left is heavy How does a fan in a turbofan engine suck air in? Now I have islanders 1-6 on side "A" and 7-12 on side "B" both groups of six are as close to the fulcrum of the see saw in a single file line as possible, one side will fall, one side will rise. Most Simple Solution to Holt's "12 men on an island with a seesaw" brainteaser! At this point we just weight S4 against a Measure the odd man (12) against any of the other men (which are all of equal weight) to determine if he is heavier or lighter. (Second Use), If the see saw balances, remove all but one from the seesaw and put one of the remaining two opposite them. New comments cannot be posted and votes cannot be cast. Can a VGA monitor be connected to parallel port? It is of indeterminate length I wish for my see saw to be long enough to place 12 on either side, but only six will be on either side of the fulcrum. You signed in with another tab or window. You signed in with another tab or window. Edit: heavier or slightly lighter. After each round, we can see if the seesaw tilted down on the left (L), right (R) or was balanced (-), The pattern of the seesaw will match the pattern of one person ( or be exactly reversed ). So in principle, we should be able to solve the problem. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. I could not add my own answer and I felt that editing that post was more work than necessary so forgive me for posting again, as well as for answering below as this was my solution to 'Holts' riddle. I gave each of the 12 men a letter, A-L. Can You Solve the Brain Teaser of the 12 Men and a See-Saw? Ackermann Function without Recursion or Stack. @emdee - Here is the link that you posted in the question. (seesaw measurement number 3), 2.B.2 if balanced After you do your fist step you will have eliminated some of the men as possiblilities (they are neutral). Find out the minimum number of times the seesaw will be used. Lift student learning and family engagement to new heights with multimodal learning tools, intuitive messaging, and research-based curriculum. If still balances, we know that the fourth one, who has not sat on the see-saw from that group is the one oddly weighted. The biggest problem is that you do not know whether the odd man is heavier or lighter. However only three measurements are allowed. Another coin weighing puzzle. seesaw: R1 L2 L3 L4 (heavy) L1 S2 S3 S4 ie. It is a good write up though. You can only use it three times. The riddle, as you'll recall, is this: There are twelve men on an island. Press J to jump to the feed. Was Galileo expecting to see so many stars? Split the men into two(2) groups 'abcdef' and '123456'. Try that and see where it takes you. put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. If they are different, the heavier of the two is the one we are looking for (and heavier). III) 1 2 3 4 < 5 6 7 8 do the same process as II with appropriate adjustments being made. The island has no escapes, but there is a seesaw. are patent descriptions/images in public domain? One of two things will happen: 1) They are equal. Note that this implies that the first comparison must yield more than 1 bit of information. Make 3 groups of 4 people each Group A: 1,2,3,4 Group B: 5,6,7,8 Group C: 9,10,11,12 Round #1: Use the seesaw with Group A and B. If they are unequal then the odd man is the one within last 2 being measured that is heavier / lighter based on the known weight difference (heavier / lighter). The ice cube and the basketball have the same weight. sideline: S1 S2 S3 S4 There are 12 men on an island. And if they are also equal then that would mean that the 12th person weighs different. Did the residents of Aneyoshi survive the 2011 tsunami thanks to the warnings of a stone marker? You must figure out which. sideline: S1 R2 R3 R4, we know that the light islander is amongst R2 R3 R4 If the seesaw is evenly balanced, then the odd one out is in group 3 or group 4. If they 9 vs 10 is balanced, then you can deduce that the 11th islander is the different weight. It is easier than everyone makes it. There are no scales or other weighing device on the island. 2) They are different. I am just looking for a little tweak to this answer. ; C1, C2. Drift correction for sensor readings using a high-pass filter. In step 3 place one unknown on each side. After spending some time with it (and finally solving it), I get why they didnt give an answer. (First Use). the first solution i had for the 99 puzzle was another see saw exploit: Initial state 1-6 against 7-12, but islanders leave the see saw in pairs, ie 1 and 12 get off at the same time 2 and 11 after, when your bad penny exits, you'll know its one of that pair as the remaining islanders will balance Theyre the 'bad pair from . Each islander is given a position to sit on the seesaw for each round. Say as example 1234 were lighter. B_ the see-saw becomes level with the ground, therefore the man of a different weight is standing with group 'abc456'. If the see saw is not balanced, remove one from each end. now switch R1 R2 R3 and S2 S3 S4 AND switch R1 AND L1. Here is a more precise retelling of the riddle we found. This page contains affiliate links, which means we may earn a small amount of money if a reader clicks through and makes a purchase. So the solution must involve cross-referencing the left, right or balanced measurements of different groups of islanders. I believe it was in. The second measurement was equal, so you know that the odd man is within the group 6-8. You can only use it three times. And there you have it! 2: Place the man from your pair who was on the lower end of the see-saw . Solution: The minimum number of times seesaw will be needed is 3. But this is simple! (Second Use). Use the third and final seesaw use to determine if the 12th person is the heavier or lighter islander (i.e. Otherwise the one who stayed is the oddly weighted one. This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. Is the set of rational points of an (almost) simple algebraic group simple? Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. I can do this in one move, where no one gets off the see saw, and they only get on it once. The side that is lighter has the men switch positions getting closer or further from the fulcrum without coming on or off the see saw, after all of the positions have been tried, if the see saw does not move, it means all the men on that side are of equal weight, if the balance is lost, the last man to move before the balance is lost is the lighter man. Can someone suggest how we can modify the answer above ? Now you know that one of the four men on one side is light. How do you do it? Are you sure you want to create this branch? 11 weigh exactly the same, but one of them is slightly lighter or heavier. There are 27 total permutations for the position of the scale which easily leaves you a symmetric configuration that allows you to determine which person it is and whether they are heavy or light every time. So, what is the 12 people on an island riddle and what is the answer? All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. There are 12 men on an island. You have to figure out which Islander is the heaviest using a seesaw. What are some tools or methods I can purchase to trace a water leak? If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. Press question mark to learn the rest of the keyboard shortcuts. You don't know if he is heavier or lighter, just that he is a different weight. If they are the same, the different man is 11, and he is heavier if 9,10,11 was heavier than 1,2,3 and he is lighter if 9,10,11 was lighter than 1,2,3. 2150 Condos - West Tower Phase 2. On one side of a balanced see-saw is an ice cube, on the other side is a basketball. You must figure out which. IF the 2 scales are unequal, then you know the odd man is in the set of 1-8. Thanks! How do you figure out which one is heavier? Death by roo roo. You have to figure out which Islander is the heaviest using a seesaw. c) If they are the same, then one of 3,4 is different. Now put 7 on one end and 8 on the other. if balanced it is S3 - else it is the lighter of S1 and S2. If balanced it is the heavy L1 else if unbalanced it is light R1. 12 Islanders Teeter Totter Riddle There is an island with 12 islanders. Can patents be featured/explained in a youtube video i.e. The only case where you dont is 1.1.1 where the seesaw balances every time and its a process of elimination, the oddly weighted person never gets on the scale so you cant know. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. You can weigh three combinations of men on the see-saw. If balanced, the 3rd unknown is heavy. we know it is either R1 or L1. Each step here corresponds to one weighing. sideline: S1 S2 S3 S4, 2.A.1 if balanced Questions: one side was lighter and is now heavier) then you know it was one of the 3 men who changed sides from the left to the right. THIS TIP WILL GIVE AWAY THE MAIN SECRET : Instead of just breaking the men up into groups and comparing those groups against each other, you can shift them from one side of the see saw to the other side. Suppose the previous two groups were 1234 and 5678, shuffle them to create a new group of 5 and 4678 then three of the third four say abcd get on with 5 to get as an example abc5 and 4678. What is the arrow notation in the start of some lines in Vim? Now, go give Holt the solution, collect your Beyonce rock concert tickets, and let him rub it in his old Captain's face. Note that this implies that the 12th person is the different weight is standing with group 'abc456.... An ( almost ) simple algebraic group simple if the measurement is equal then that would mean the... 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May belong to any branch on this repository, and research-based curriculum with learning! Yield more than 1 bit of information L4 ( heavy ) L1 S2 S3 ie... Teeter Totter riddle there is an ice cube and the basketball have the same amount, but there an! Can you solve the Brain Teaser of the 12 people on an island to! Water leak recall, is this: there are twelve men on an.., and may belong to any branch on this repository, and research-based.! More than 1 bit of information student learning and family engagement to new heights with learning. The 11th islander is given a position to sit on the lower end of the keyboard.!
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